Saturday, February 1, 2020

Sneaky Trick with Systems of LInear Equations on the SAT

From the no calculator section of the May 2018 SAT

  11                                                                            
       
                               5x + 2y = 22
                                4x + y = 17

In the system of equations above, what is the value 
of x + y ?

A) 5
B) 4
C) 3
D) 2

To solve by elimination, I would (1) multiply the second equation by -2, (2) add the equations, (3) solve for y, (4) substitute back in to find x, and (5) add x and y.

(1)   
      5x + 2y = 22
  -2[4x + y = 17]

      5x + 2y = 22
     -8x + -2y = -34

(2)
      [5x +  2y =  22]
    +[-8x + -2y = -34]
      -3x +  0  = -12

(3)
     x = 4


(4)
      5(4) + 2y = 22
      2y=2
        y=1

(5)       x + y = 5

This is not terribly difficult, but there is a much quicker way to solve the problem. Simply subtract the second equation from the first.            
                      [5x + 2y = 22]
                     -[4x + y = 17]
                         xy =  5

It is rather interesting how often the SAT pulls this little trick, e.g., October 2018.

  191                                                                           
2x + 3y = 1200
3x + 2y = 1300

Based on the system of equations above, what is the value of 5x + 5y?

Once again, it is possible to solve for x and y, but adding the equations yields

   [2x + 3y = 1200]
+[3x + 2y = 1300] 

   5x + 5y = 2500.

This trick doesn't always work. Sometimes the question asks for the value of either x or y by itself, making it necessary to solve for the individual variable. Nevertheless, any time a question asks for the sum or difference of the variables or multiples of the variables (x + y, x - y, 2x + 3y) it's worth looking to see what happens when the equations are simply added or subtracted.